Suppose we have a union of three queries:
union = query1 | query2 | query3
union.all_ = True
Why does the ALL key only apply to the union of query2 and query3?
We need the ALL key to be applied to all union operations.
union = query1 | query2
union.all_ = True
union |= query3
union.all_ = True
Is it correct?
Because __or__ operator is binary so you create a first union which is union-ed again with the last one. This is the last union that you get.
Well you can just write:
union = Union(query1, query2, query3, all_=True)
Thank you for the tip.
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