I have this record block in module xml:
<!-- RPA Projects -->
<!-- Menu entry -->
<record model="ir.action.act_window" id="act_rpa_project_form">
<field name="name">RPA Projects</field>
<field name="res_model">afx.project</field>
</record>
<record model="ir.action.act_window.view" id="act_rpa_project_form_view1">
<field name="sequence" eval="10"/>
<field name="view" ref="project_view_list"/>
<field name="act_window" ref="act_rpa_project_form"/>
</record>
<record model="ir.action.act_window.view" id="act_rpa_project_form_view2">
<field name="sequence" eval="20"/>
<field name="view" ref="project_view_form"/>
<field name="act_window" ref="act_rpa_project_form"/>
</record>
<!--/ End of Menu entry -->
<!-- Tabs definitions -->
<record model="ir.action.act_window.domain" id="act_rpa_project_domain_rpa">
<field name="name">RPA</field>
<field name="sequence" eval="10"/>
<field name="domain"
eval="[('team', '=', 'RPA')]"
pyson="1"/>
<field name="count" eval="False"/>
<field name="act_window" ref="act_rpa_project_form"/>
</record>
<!--/ End of Tabs definitions -->
<!--/ End of RPA Projects -->
So when a person click on RPA Projects nav button, it will open a list only projects that assigned to “RPA” team. As below:
But now, my boss want me to set default team’s name on the creation of a project tobe “RPA” without needed the user to choose from clicking the search button at project form as below:
My question, is there a way to di this from XML file? If there isn’t then I will try via class level.
Thanks in advance
Bromo